If the equation 2 {sin ^2}x + frac{{sin | vedclass

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Question

$-\cos 2 x+\frac{\sin 2 x}{2}=k-1$

$-\frac{\sqrt{5}}{2} \leq k-1 \leq \frac{\sqrt{5}}{2}$

$ \Rightarrow 1-\frac{\sqrt{5}}{2} \leq k \leq 1+\frac

Vedclass · Accepted Answer

$3$

Vedclass · Answer

$-\cos 2 x+\frac{\sin 2 x}{2}=k-1$

$-\frac{\sqrt{5}}{2} \leq k-1 \leq \frac{\sqrt{5}}{2}$

$ \Rightarrow 1-\frac{\sqrt{5}}{2} \leq k \leq 1+\frac{\sqrt{5}}{2}$

$	herefore \operatorname{sum}=0+1+2=3$

If the equation $2\ {\sin ^2}x + \frac{{\sin 2x}}{2} = k$ , has atleast one real solution, then the sum of all integral values of $k$ is

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